# Need help with math, again.

Discussion in 'The Guru's Pub' started by .:JeeBus:., Feb 23, 2010.

1. ### .:JeeBus:.Master Guru

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So, in my math h/w, I have to find a solution in two variables and I've been doing fine, until they had introduced fractions. My math book fails because they don't tell you how to do fractions, so, I have to come to you guys. So, the problem is, 1/5x + 9 =y and they want me to find 4 solutions, so.. help?
(1/5x is a fraction.)

2. ### PuddingWagonMaha Guru

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Substitute in some values for x (where x =/= 0, since 1/0 is undefined) and find the corresponding y values.

When x = 1, you find that y = 1/5 + 9 = 46/5
When x = 2, you find that y = 1/10 + 9 = 91/10
etc

Surely I'm missing something here.

3. ### DustpuppyAncient Guru

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etc: man I'm not on my game today I shall go die in shame soon

as well as correct my post.

If you're not being asked just to plug any old thing into the equation as puddingwagon & I both initially read that . Is something like this what you're looking for?

1/(5x) +9 =y

1/(5x) = y-9

1/x = 5y-45

1 = (5y-45)x

1/(5y-45) = x?

Last edited: Feb 23, 2010

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5. ### TroMAncient Guru

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First of all, if you want us to help you with YOUR HOMEWORK write the equation in a way that doesn't confuse us... is it

(1/5x)+9 or 1/(5x+9)? Is the 5x-9 under the 1 or is just the 5x just under the 1?

6. ### nvlddmkmBanned

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Is a Klein Bottle a singularity?

7. ### DustpuppyAncient Guru

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I am glad I will not spend my life asking that.

8. ### SinacleMaster Guru

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To prove all numbers X are possible:

1/5x + 9 =y

x + 45 = 5y

x = 5y -45

x = 5(1/5x+9) - 45

x = x +45 -45

x = x

So all numbers hold. X can be any number. You can calculate Y using your first equation, like PuddingWagon did.

Last edited: Feb 23, 2010