So, in my math h/w, I have to find a solution in two variables and I've been doing fine, until they had introduced fractions. My math book fails because they don't tell you how to do fractions, so, I have to come to you guys. So, the problem is, 1/5x + 9 =y and they want me to find 4 solutions, so.. help? (1/5x is a fraction.)

Substitute in some values for x (where x =/= 0, since 1/0 is undefined) and find the corresponding y values. When x = 1, you find that y = 1/5 + 9 = 46/5 When x = 2, you find that y = 1/10 + 9 = 91/10 etc Surely I'm missing something here.

etc: man I'm not on my game today I shall go die in shame soon as well as correct my post. If you're not being asked just to plug any old thing into the equation as puddingwagon & I both initially read that . Is something like this what you're looking for? 1/(5x) +9 =y 1/(5x) = y-9 1/x = 5y-45 1 = (5y-45)x 1/(5y-45) = x?

First of all, if you want us to help you with YOUR HOMEWORK write the equation in a way that doesn't confuse us... is it (1/5x)+9 or 1/(5x+9)? Is the 5x-9 under the 1 or is just the 5x just under the 1?

To prove all numbers X are possible: 1/5x + 9 =y x + 45 = 5y x = 5y -45 x = 5(1/5x+9) - 45 x = x +45 -45 x = x So all numbers hold. X can be any number. You can calculate Y using your first equation, like PuddingWagon did.